php判断正常访问和外部访问的示例
内容摘要
php判断正常访问和外部访问 复制代码 代码如下: <?php session_start(); if(isset($_POST['check'])&&!empty($_POST['name'])){ if($_POST['check'] == $_SESSION['check']
文章正文
php判断正常访问和外部访问
<?php
session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
if($_POST['check'] == $_SESSION['check']){
echo "正常访问";
}else{
echo "外部访问";
}
}
$token = md5(uniqid(rand(),true));
$_SESSION['check'] = $token;
?>
<form method="post" action="">
<input type="text" name="name"/>
<input type="text" name="check" value="<?=$token;?>">
<input type="submit">
复制代码 代码如下:
<?php
session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
if($_POST['check'] == $_SESSION['check']){
echo "正常访问";
}else{
echo "外部访问";
}
}
$token = md5(uniqid(rand(),true));
$_SESSION['check'] = $token;
?>
<form method="post" action="">
<input type="text" name="name"/>
<input type="text" name="check" value="<?=$token;?>">
<input type="submit">
代码注释
作者：喵哥笔记
