JAVA 18位身份证号码校验码的算法
2022-10-29 18:24:17内容摘要
public static char doVerify(String id) { char pszSrc[]=id.toCharArray(); int iS = 0; int iW[]={7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2}; char szVerC
文章正文
public static char doVerify(String id)
{
char pszSrc[]=id.toCharArray();
int iS = 0;
int iW[]={7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
char szVerCode[] = new char[]{'1','0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
int i;
for(i=0;i<17;i++)
{
iS += (int)(pszSrc[i]-'0') * iW[i];
}
int iY = iS%11;
return szVerCode[iY];
}
{
char pszSrc[]=id.toCharArray();
int iS = 0;
int iW[]={7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
char szVerCode[] = new char[]{'1','0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
int i;
for(i=0;i<17;i++)
{
iS += (int)(pszSrc[i]-'0') * iW[i];
}
int iY = iS%11;
return szVerCode[iY];
}
代码注释
作者：喵哥笔记
