php检查字符串是否包含7位GSM字符的解决办法

内容摘要
这篇文章主要为大家详细介绍了php检查字符串是否包含7位GSM字符的简单示例,具有一定的参考价值,可以用来参考一下。

对php检查字符串中是否包含7位的GSM字符对此感兴趣的朋友
文章正文

这篇文章主要为大家详细介绍了php检查字符串是否包含7位GSM字符的简单示例,具有一定的参考价值,可以用来参考一下。

对php检查字符串中是否包含7位的GSM字符对此感兴趣的朋友,看看idc笔记做的技术笔记!下面的代码检查一个字符串是否包含任何7位GSM字符。它对短信平台上工作的人非常有用。

/**
 * php检查字符串中是否包含7位的GSM字符
 *
 * @param 
 * @arrange 512-笔记网: 512Pic.com
 **/
<?php 
function check_gsm($str) 
{ 
	$arr = array( 
"0x00", "0x01", "0x02", "0x03", "0x04", "0x05","0x06","0x07","0x08","0x09", 
"0x0A","0x0B","0x0C","0x0D","0x0E","0x0F","0x10","0x11","0x12","0x13", 
"0x14","0x15","0x16","0x17","0x18","0x19","0x1A","0x1B","0x1B0A", 
"0x1B14","0x1B28","0x1B29","0x1B2F","0x1B3C","0x1B3D","0x1B3E", 
"0x1B40","0x1B65","0x1C","0x1D","0x1E","0x1F","0x20","0x21","0x22", 
"0x23","0x24","0x25","0x26","0x27","0x28","0x29","0x2A","0x2B","0x2C", 
"0x2D","0x2E","0x2F","0x30","0x31","0x32","0x33","0x34","0x35","0x36", 
"0x37","0x38","0x39","0x3A","0x3B","0x3C","0x3D","0x3E","0x3F","0x40", 
"0x41","0x42","0x43","0x44","0x45","0x46","0x47","0x48","0x49","0x4A", 
"0x4B","0x4C","0x4D","0x4E","0x4F","0x50","0x51","0x52","0x53","0x54", 
"0x55","0x56","0x57","0x58","0x59","0x5A","0x5B","0x5C","0x5D","0x5E", 
"0x5F","0x60","0x61","0x62","0x63","0x64","0x65","0x66","0x67","0x68", 
"0x69","0x6A","0x6B","0x6C","0x6D","0x6E","0x6F","0x70","0x71","0x72", 
"0x73","0x74","0x75","0x76","0x77","0x78","0x79","0x7A","0x7B","0x7C", 
"0x7D","0x7E","0x7F"); 
	$strl = strlen($str); 
	for ($i = 0;$i < $strl; $i++) 
	{ 
		$char = '0x' . bin2hex(substr($str,$i,1)); 
		$pos = in_array($char,$arr); 
		if ($pos == 1) 
		{ 
			$j++; 
		} 
	} 
	if ($j < $strl) 
	{ 
		return false; 
	} 
	else 
	{ 
		return true; 
	} 
} 

/***   来自php教程(www.idcnote.com)   ***/

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代码注释

作者:喵哥笔记

IDC笔记

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