python面试题简单罗列

这篇文章主要为大家详细介绍了python面试题简单罗列，具有一定的参考价值，可以用来参考一下。

# 来自www.idcnote.com 
一些初级python面试题，这里简单罗列一下
# 反转字符串， 这个是最常见的
# 比如给一个字符串hello,将其反转为olleh
def reverse(str):
  alist = list(str)
  alist.reverse()
  new_str = ''.join(alist)
  return new_str


 
 
# 写一个方法打印如下内容,每一行打印5个
# server1, server2, server3, server4, server5(换行)
# server6, server7, server8, server9, server10(换行)
# server11, server12, server13, server14, server15(换行)
# server16, server17, server18, server19, server20(换行)
# ...
# server996, server997, server998, server999, server1000

#正确写法1
for i in range(1,1000):
  if (i % 5 == 1):
    a = i + 1
    b = i + 2
    c = i + 3
    d = i + 4
    print('server' + str(i) + ', ' + 'server' + str(a) + ', ' + 'server' + str(b) + ', ' + 'server' + str(c) + ', ' 'server' + str(d))

#正确写法2
for i in range(1,1004):
  if (i % 5 == 0):
    a = i - 4
    b = i - 3
    c = i - 2
    d = i - 1
    print('server' + str(a) + ', ' + 'server' + str(b) + ', ' + 'server' + str(c) + ', ' + 'server' + str(d) + ', ' 'server' + str(i))

#注意难点
#print语句每运行一次，都是另起一行，因此完全不必要写一个\n

#以下是错误写法
for i in range(1,1000):
  if (i % 5 == 0):
   print('server' + str(i) + '\n')
  else:
    print('server' + str(a) + ', ')
#这种写法的运行结果是
server1,
server2,
server3,
server4,
server5

server6,
server7,
server8,
server9,
server10

server11,
server12,
server13,
server14,
server15

server16,
......



# 给一个dir, 循环遍历该dir下面的所有文件(只列出文件, 不要文件夹).
import os
def get_file_names(dir):

  alist = os.listdir(dir)
  path = os.path.realpath(dir)
  result = []
  for i in alist:
    ipath = os.path.join(path,i)
    if os.isdir(ipath):
      #get_file_name(ipath)
      result.extend(get_file_name(ipath))
    else:
      result.append(ipath)
  return result

 
 
 
# Given an array of integers, return indices of the two numbers
# such that they add up to a specific target.
# You may assume that each input would have exactly one solution.
# 给了一个全是数字的列表,现在让列表中任意2个数字相加, 得到一个指定target,
# 然后返回这2个数字的index
# Example:
# Given nums = [2, 7, 11, 15], target = 9,
#
# Because nums[0] + nums[1] = 2 + 7 = 9,
# return [0, 1].
def two_sum(nums, target):

  for a in (0,len(nums)):
    b = a + 1
    res1 = 0
    res2 = 0

    for i in (b,len(nums)):
      if ( nums[a] + nums[i] == target ):
        res1 = a
        res2 = i
  return [res1, res2]

注：关于python面试题简单罗列的内容就先介绍到这里，更多相关文章的可以留意