PHP+MySQL实现的简单投票系统实例
内容摘要
本文实例讲述了PHP+MySQL实现的简单投票系统。分享给大家供大家参考,具体如下:
<html>
<head><title>手机系统调查问卷</title>
<style type="text/css">
<!--
span{
widt
<html>
<head><title>手机系统调查问卷</title>
<style type="text/css">
<!--
span{
widt
文章正文
本文实例讲述了PHP+MySQL实现的简单投票系统。分享给大家供大家参考,具体如下:
<html> <head><title>手机系统调查问卷</title> <style type="text/css"> <!-- span{ width:600px; height:100px; background-color:write; postion:relative; border:1px #cccccc solid; } div{ width:60px; height:1px; background-color:blue; postion:absolute; bottom:0; } --> </style> </head> <body> 你现在使用的手机是什么系统? <form id="form1" method="POST" action="count.php"> <input type="radio" name="phone" value="1"> Android安卓 <input type="radio" name="phone" value="2"> Symbian塞班 <br> <input type="radio" name="phone" value="3"> iphone苹果 <input type="radio" name="phone" value="4"> Google谷歌 <br> <input type="radio" name="phone" value="5"> Winphone微软 <input type="radio" name="phone" value="6"> 其它 <br> <input type="submit" value="提交"> </form> <span> 当前票数:<br> <?php include 'connect.php'; $sql="select answer from countone"; $rs=mysql_query($sql); $total=mysql_num_rows($rs); $sql="select * from countone where answer=1"; $rs=mysql_query($sql); $android=mysql_num_rows($rs); $sql="select * from countone where answer=2"; $rs=mysql_query($sql); $symbian=mysql_num_rows($rs); $sql="select * from countone where answer=3"; $rs=mysql_query($sql); $iphone=mysql_num_rows($rs); $sql="select * from countone where answer=4"; $rs=mysql_query($sql); $google=mysql_num_rows($rs); $sql="select * from countone where answer=5"; $rs=mysql_query($sql); $winphone=mysql_num_rows($rs); $sql="select * from countone where answer=6"; $rs=mysql_query($sql); $other=mysql_num_rows($rs); ?> <table border="0"> <th>android</th><th>Symbian</th><th>iphone</th><th>Google</th><th>winphone</th><th>other</th> <tr> <td><?php echo $android ?>票</td> <td><?php echo $symbian ?>票</td> <td><?php echo $iphone ?>票</td> <td><?php echo $google ?>票</td> <td><?php echo $winphone ?>票</td> <td><?php echo $other ?>票</td> </tr> <tr> <td><?php for ($i=1;$i<=$android/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> <td><?php for ($i=1;$i<=$symbian/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> <td><?php for ($i=1;$i<=$iphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> <td><?php for ($i=1;$i<=$google/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> <td><?php for ($i=1;$i<=$winphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> <td><?php for ($i=1;$i<=$other/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td> </tr> </table> </span> </body> </html>
写的有点啰嗦,有点笨但很实用
<?php include 'connect.php'; $name=$_POST['phone']; $sql="insert into countone values(null,$name,now(),null)"; mysql_query($sql); ?> <script type="text/javascript"> alert ("投票成功!"); location="question.php"; </script>
链接mysql:
<?php mysql_connect("localhost","root",""); mysql_select_db("vote"); mysql_query("set names utf8"); ?>
更多关于PHP相关内容感兴趣的读者可查看本站专题:《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》
希望本文所述对大家PHP程序设计有所帮助。
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